Triangle Problem
A conveyor belt is leaning against the top of a 38 foot wash tower. The distance from where the conveyor belt touches the ground and the top of the wash tower is 180 feet. It is not known if the angle formed between the wash tower and the ground is a right angle. What is the range of possible angle measures for the angle formed by the conveyor belt and the ground?
9 comments:
I set up the triangle on paper
and then i used the law of sines:
(sin(90))/180=(sin(x))/38
then i cross multiplied
(sin(90))(38)=(sin(x))(180)
(1)(38)=(sin(x))(180)
(38)/(180)=(sin(x))
.211111111=(sin(x))
then i used inverse sign and got an angle of 12.19 degrees
I set up the problem on paper as a triangle, used Law of Sines, and figured it out to be between 12 and 13 degrees...or x<90, either one
I used the law of sines.
1)Sin x= o/h
2)I did 2nd SIN and put (38/180) and got 12.19 degrees
so the angle is less than 90 degrees.
i used the law of sines to get .211111 then i hit the inverse sine button to come up with a number of 12.19
so the angle has to be less than 90
I drew the picture and then I used the law of sines to answer this question:
180/sin90 = 38/sinX
38 sin90 = 180 sinX
38= 180 sinX
.21111 = sinX
sin(-1)X= 12.1874
i also used law of sines, then the inverse, and found 12.19 to be the answer.
Law of Sines cannot be used. The angle between the building and the ground may not be a right angle.
The Problem states that the angle between the ground and the watertower is not specified to be a right angle. Making 1/2 of the answers given, incorrect
first i drew out the problem and labeled everything. then i used law of sines to get 2.11 repeating. then i used inverse sin and got 12.19. so the range of the angle must be 0 < 12.19
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